Max,
I think the power gain at 25 MHz for your model of the biconical
dipole is high because your model assumes perfectly conducting wires.
The power gain is computed using the total input power, but directive
gain is based on the input power decreased by the power dissipated in
lumped and distributed loads on the wires and in non-radiating
networks. So, if the wires in your model are unloaded, the power gain
will be the same as the directive gain. If you use an LD line, you
can give the wires the appropriate conductivity. Then, the ohmic
losses due to the finite conductivity will be comparable to the 0.2
ohms input impedance, and the efficiency will decrease. The power
gains should then drop down into the negative-dBi region. Good luck.
Bill
Received on Tue Aug 19 1997 - 22:52:41 EDT
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